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Автор - taptall2000

Пожалуйста помогите:)
Lim
X^2+2x-8/8-x^3
X->2

Ответ

Автор - moboqe

displaystyle lim_{xto2}{x^2+2x-8over8-x^3}=lim_{xto2}{(x-2)(x+4)over(2-x)(4+2x+x^2)}=-lim_{xto2}{(x-2)(x+4)over(x-2)(4+2x+x^2)}=-lim_{xto2}{x+4over4+2x+x^2}=-{6over4+4+4}=-{1over2}

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