Автор - viper1206

Решите уравнение
1+sin 2x = 2 sin x + cos x.
Срочно дам 20 баллов​

Ответ

Проверено экспертом

Автор - Universalka

1 + Sin2x = 2Sinx + Cosx

1 + 2SinxCosx - 2Sinx - Cosx = 0

(2SinxCosx - 2Sinx) + ( 1 - Cosx) = 0

2Sinx(Cosx - 1) + (1 - Cosx) = 0

2Sinx(Cosx - 1) - (Cosx - 1) = 0

(Cosx - 1)(1Sinx - 1) = 0

left[begin{array}{ccc}Cosx-1=0\2Sinx-1=0end{array}right\\\left[begin{array}{ccc}Cosx=1\Sinx=frac{1}{2} end{array}right\\\left[begin{array}{ccc}x=2pi n,nin Z \x=(-1)^{n}arcSinfrac{1}{2}+pi n,nin Zend{array}right\\\left[begin{array}{ccc}x=2pi n,nin Z \x=(-1)^{n}frac{pi }{6}+pi n,nin Z end{array}right

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