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maksimcat

Ответ:

Объяснение:

x^2+5y^2-4xy+2x-6y+2.5=\ \x^2-4xy+4y^2+y^2+2x-2y-4y+1+1.5=\ \(x^2-4xy+4y^2)+(y^2-2y+1)+2(x-2y)+1+0.5=\ \ ((x-2y)^2+2(x-2y)+1)+(y-1)^2+0.5=\ \(x-2y+1)^2+(y-1)^2+0.5>0

квадрат любого числа ≥0

первые два слагаемых ≥0;0.5>0

ч.т.д.

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