Автор - ablodal
Ответ:
1) 100 2) 90 3) 60 4) 30
Пошаговое объяснение:
1) 4a+5b+12+2a+4+9b=(4*a+2*a)+(5*b+9*b)+(12+4)=(4+2)a+(5+9)b+16=6a+14b+16
a = 7, b = 3, => 6a+14b+16=6*7+14*3+16 = 100
2) 12c+d+7+8d+3c+5=(12*c+3*c)+(1*d+8*d)+(7+5) = (12+3)c+(1+8)d+12 = 15c+9d+12
c = 4, d=2, => 15c+9d+12 = 15*4+9*2+12 = 90
3) 9+2m+4k+6+3m+k = (2*m+3*m)+(4*k+1*k)+(9+6)=(2+3)m+(4+1)k+15 = 5m+5k+15
m = 8, k=1, => 5m+5k+15 = 5*8+5*1+15 = 60
4) 5x+2+y+17+7y+6x = (5*x+6*x)+(1*y+7*y)+(2+17)=(5+6)x+(1+7)y+19=11x+8y+19
x = 1, y=0, => 11x+8y+19=11*1+8*0+19 = 30