Автор - sofa8253

Решите неравенства:
1) 2(3x+1) – х = 3(x+4);
3) 2(x-1) - 3(х + 2) < 6(1 + х);
2) 7х + 4(х – 2) > 6(1 + 3х);
4) 7(у + 3) - 2 (y+2) 2(5+1)​

Ответ

Автор - darinaursu007
1)2(3x+1)-x=3(x+4)
6x+2-x=3x+12
5x+2=3x+12
5x-3x=12-2
2x=10
x=5
4)7(y+3)-2(y+2)2(5+1)
7y+21-2(y+2)•2•6
7y+21-24(y+2)
7y+21-24y-48
-17y-27
остальное не поняла

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