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Ответ

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katherina09140

Ba(OH)2 + H2SO4 = BaSO4 + 2H20

m(H2SO4)=20г*0.5 = 10 г

n(H2SO4)=10г/98г/моль=0,1моль

Кислота не в избытке

m(BaSO4)=0.1моль*233г/моль=23.3г

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