Ответ Автор - selmash21 =(7х-7у)+(бх-бу)=7(х-у)+б(х-у)=(х-у)(7+б)$$$$$$$$=(pq+q)-(x+px)=q(p+1)-x(1+p)=(p+1)(q-x)$$$$$$$$=(2cx-cy)-(6x-3y)=c(2x-y)-3(2x-y)=(2x-y)(c-3)$$$$$$$$$=(56pq+8p)-(1+7q)=8p(7q+1)-1(1+7q)==(7q+1)(8p-1)