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Ответ

Ответ дан
wieslawlozickip5w1nd

Ответ:

Объяснение:

1)

IACI²=17²-8²=289-64=225

IACI=15

sinα=8/17

cosα=IACI/17=15/17

tgα=8/IACI=8/15

sinβ=IACI/17=15/17

cosβ=8/17

tgβ=IACI/8=15/8

2)

IABI²=21²+20²=441-400=841

IABI=29

sinα=21/IABI=21/29

cosα=20/IABI=20/19

tgα=21/20

sinβ=20/IABI=20/29

cosβ=21/IABI=21/29

tgβ=20/21

3)

IABI²=1²+2²=1+4=5

IAB=√5

sinα=1/IABI=1/√5=√5/5

cosα=2/IABI=2/V5=2V5/5

tgα=1/2

sinβ=2/AB=2/√5=2√5/5

cosβ=1/AB=1/√5=√5/5

tgβ=2/1=2

4)

IBCI²=25²-24²=265-576=49

IBCI=7

sinα=IBCI/25=7/25

cosα=24/25

tgα=IBCI/24=7/24

sinβ=24/25

cosβ=IBCI/25=7/25

tgβ=24/IBCI=24/7

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