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manyny06

Ответ:

решение смотри на фотографии

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NNNLLL54

(3sqrt{24}+sqrt3):sqrt3-3sqrt2=frac{3sqrt{24}+sqrt3}{sqrt3}-3sqrt2=frac{3sqrt{24}}{sqrt3}+frac{sqrt3}{sqrt3}-3sqrt2=\\=sqrt3cdot sqrt{24}+1-3sqrt2=sqrt3cdot sqrt{3cdot 4cdot 2}+1-3sqrt2=3cdot 2sqrt2+1-3sqrt2=\\=6sqrt2+1-3sqrt2=3sqrt2=1

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