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Ответ дан
CarrotAnne

Задача 7.

BCD+ACD=180 (смежные)

BCD=120 (по условию)

ACD=60

ACD=ACE+DCE

ACE=DCE=60:2=30

BCE=BCD+DCE

BCE=120+30=150

Ответ: 150

ЗАДАЧА 10.

BOE+AOE=180 (смежные)

BOE=30 (по условию)

AOE=150

BOC+AOC=180 (смежные)

BOC=90 (по условию)

AOC=180-90=90

AOC=90

AOC=AOD+DOC

AOD=DOC=90:2=45

BOC=BOE+COE

BOE=30

BOC=90

COE=90-30=60

DOE=DOC+COE

DOE=45+60=105

Ответ: 105.

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