Автор - katushkas77

Помогите, 20 баллов, задание на фото

Ответ

Автор - drakerton

Ответ:

1.1) 0,1sqrt{900} - frac{1}{4}sqrt{64} = frac{30}{10} - frac{8}{4} = 3 - 2 = 1\\

1.2) sqrt{25}*sqrt{0,04}+sqrt{3^3+22} = 5*0,2+sqrt{27+22} = 1+sqrt{49} = 8\\

1.3) 4sqrt{0,49} - sqrt{8^2+15^2} = 4*0,7 - sqrt{64+225} = 2,8 - sqrt{289} = 2,8 - 17 = -14,2\\

1.4) sqrt{2frac{2}{49}} +sqrt{2frac{7}{9}} - 0,03sqrt{40000} = sqrt{frac{100}{49}}   +sqrt{frac{25}{9}} - 0,03*200 = frac{10}{7} + frac{5}{3} - 6 =\\ frac{30 + 15}{21} - 6 = frac{45}{21} - 6 = 2frac{3}{21} - 6 = 2frac{1}{7} - 6 = -4frac{1}{7}

2.1) (sqrt{7})^2 - sqrt{1,21} = 7 - 1,1 = 5,9\\

2.2) (4sqrt{3})^2 - (3sqrt{5})^2 = 16*3 - 9*5 = 48 - 45 = 3\\

Ответ

Автор - Svetlana565

#1

1) 0.1*sqrt{900}-1/4*sqrt{64}=0.1*30-0.25*8=3-2=1

2) sqrt{25}*sqrt{0.04}+sqrt{3^3+22}=5*0.2+7=8

3) 4sqrt{0.49} -sqrt{8^2+15^2} =4*0.7-sqrt{289} =2.8-17=-14.2

#2

1) (sqrt{7}) ^2-sqrt{1.21}=7-1.1=5.9

2) (4sqrt{3} )^2-(3sqrt{5} )^2=16*3-9*5=48-45=3

3) 32*(-1/2sqrt{11})^2=32*1/4*11=8*11=88

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