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Ответ

Ответ дан
ksenia2751
x^2=6^2+18^2-2*6*18*cos60°
x^2=36+324-2*6*18*1/2
x^2=360-108=252
x=6 корней из 7

Ответ

Ответ дан
wieslawlozickip5w1nd

по формулье косинусoв

x²=6²+18²-2*6*18*cos 60 ,  cos60 градусов =1/2

x²=36+324-216*1/2

x²=36+324-108=360-108=252

x=V252=2V63 ≈ 16

OTBET: третья сторона треыгольника равна  2V63≈  16 j


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