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Ответ

Автор - MusWane

Ответ:

4) 25 кБ

Объяснение:

Общее число символов на странице - 32 * 25 = 800;

Общее число символов в статье - 800 * 32 = 25600;

Информационный объем статьи - 25600 * 8 = 204800 бит,

204800 / (8 * 1024) = 25 кБ

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