Автор - yarilomoi

Разложите на множители:

2ху – 3ху2;
8b4 + 2b3;
х (х – у) + а (х – у);
2а – 2b + са – сb;
2а – ас – 2с + с2;
bx + by – х – у – ах – ау.

Ответ

Автор - NapoleonHill

xy(2-3y)

2b³(b+2)

(x-y)(x+a)

a(2+c)-b(2+c)=(c+2)(a-b)

2(a-c)-c(a-c)=(a-c)(2-c)

x(b-a-1)+y(b-a-1)=(b-a-1)(x+y)

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