Автор - ая20041

помогитеееее плииз 435 и 436

Ответ

Автор - taisasnitko

435.1)1-cos²α-sin²α=1-(cos²α+sin²α)=1-1=0.

2)sin²α-(1-2cos²α)=sin²α-(sin²α+cos²α-2cos²α)=sin²α-(sin²α-cos²α)=sin²α-sin²α+

+cos²α=cos²α.

3)=2cos²α-1-2sin²α=2(cos²α-sin²α)-1=2cos2α-1.

436.1)cosα·sinα·tgα=cosα·sinα·sinα/cosα=sin²α.

2)sinαcosαtgα -1=sin²α-1= -(1-sin²α)= -cos²α.

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