Автор - axi676

найти |a+b| если |а|=12 |b|=21 и |а-b|=30 ​

Ответ

Автор - Namib

Ответ:

3 sqrt{30}

Пошаговое объяснение:

  {(a - b)}^{2}  =  {a}^{2}  - 2ab +  {b}^{2}  \ 2ab =  {a}^{2}  +  {b}^{2}  -  {(a - b)}^{2}  \ {(a  + b)}^{2}  =  {a}^{2}   +  2ab +  {b}^{2} = \  =  2( {a}^{2}  +  {b}^{2} ) -  {(a - b)}^{2}  =  \  = 2( { |a| }^{2}  +  { |b|}^{2} ) -  { |a - b| }^{2} =  \ 2( {12}^{2}  +  {21}^{2} ) -  {30}^{2} =  \  = 2(144 + 441) - 900 = \  =  1170 - 900 = 270 \   { |a + b| }^{2}  = 270 \  |a + b|  =  sqrt{270}  = 3 sqrt{30}

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