Ответ Автор - takushnir (3х+π/3)=(-1)ⁿarcsin(√2/2)+πn; n∈3х+π/3=(-1)ⁿπ/4+πn; n∈Z3х=(-1)ⁿπ/4-π/3+πn; n∈Zх=(-1)ⁿπ/12-π/9+πn/3; n∈Z