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Автор - ксюнечка73829129

41.16)))
Заранее спасибо)))

Ответ

Автор - nKrynka
1) y = x³*tgx
y` = 3x² * tgx + x³/cos²x
2)  y = cosx * ctgx
y` = - sinx*ctgx - cosx/sin²x
3)  y = (1/x)*ctgx
y` = -1/√x * ctgx - 1 / (x*sin²x)
4)  y=  sinx*tgx
y` = cosx*tgx + sinx/cos²x

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