Автор - Lisenok341

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Ответ

Автор - terekosmayev

(x + 7)(7 - x) + 5x(3 - x) =  \  - (x + 7)(x - 7) + 15x - 5 {x}^{2}  =  \  -  {x}^{2}  + 49 - 5 {x}^{2}  + 15x =  \  - 6 {x}^{2}  + 15x + 49

(y - 4) ^{2}  - (y - 3)(y + 4) =  \  {y}^{2}  - 8y  + 16 -  {y}^{2}  - y + 12 =  \  - 9y + 28

32x - 5(x - 3) ^{2}  =  \ 32x - 5 {x}^{2}   + 30x - 45 =  \  - 5 {x}^{2}  + 62x - 45

2

x^{3}  - 4x = x( {x}^{2}  - 4) =  \ x(x - 2)(x + 2)

y {x}^{2}  + 2yx + y =   \ y ( {x}^{2}  + 2x + 1) = y( {x + 1)}^{2}

 {x}^{2}  + x -  {y}^{2}  - y = \   ( {x}^{2}  -  {y}^{2} ) + (x - y) =  \ (x + y)(x - y) + (x - y) =  \ (x - y)(x + y + 1)

9x -  {x}^{3}  = 0 \ x(9 -  {x}^{2} ) = 0 \ x = 0 \  {x}^{2}  = 9 \ x = 3 \ x =  - 3

3 {x}^{2}  + 27x = 0 \ 3x(x + 9) = 0 \ x = 0 \ x =  - 9

2x(8 - 3 {x}^{2} ) +  {(3x +  {x}^{2}) }^{2}  -  {x}^{2} (x - 5)(x + 5) =  \ 16x - 6 {x}^{3}  + 9 {x}^{2}  + 6 {x}^{3}  +  {x}^{4 }  -  {x}^{4}  + 25 {x}^{2}  \ 34 {x}^{2}  + 16x

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