Автор - 152315

решите систему уравнений
 {x}^{2}  +  {y}^{2}  = 26 \ x - y =  - 4

Ответ

Автор - trscott

y = x+4

x²+(x+4)² = 26

2x²+8x+16 = 26

x²+4x -5 = 0

(x+5)(x-1) = 0

y = x+4

x₁ = -5, y₁ = -1

x₂ = 1, y₂ = 5

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