Автор - ovanesova2005

Помогите пожалуйста выполнить домашнее задание номер 5.8 и 5.9 и другие номера

Ответ

Автор - HelenaWright
5.8

1)
1 +  {a}^{2}  - 2a :  =  {a}^{2}  - 2a + 1 =  {(a - 1)}^{2}
2)
4xy +  {y}^{2}  +  {4x}^{2}  = 4 {x}^{2}  + 4xy +  {y}^{2}  =  {(2x + y)}^{2}
3)
28ab + 49 {a}^{2}  + 4 {b}^{2}  = 49 {a}^{2}  + 28ab + 4 {b}^{2}  =  {(7a + 2b)}^{2}
4)
10mn + 100 {m}^{2}  + 0.25 {n}^{2}  = 0.25 {n}^{2}  + 10mn + 100 {m}^{2}  =  {(0.5n + 10m)}^{2}
5)
 frac{1}{4}  {a}^{2}  + 4 {b}^{2}  - 2ab =  frac{1}{4}  {a}^{2}  - 2ab + 4 {b}^{2}  =  { (frac{1}{2} a - 2b)}^{2}
6)
8ab +  {b}^{2}  + 16 {a}^{2}  = 16 {a}^{2}  + 8ab +  {b}^{2}  =  {(4a + b)}^{2}
5.9

1)
 {a}^{2}  + 2ac +  {c}^{2}  =  {(a + c)}^{2}
2)
 {m}^{2}  - 2mn +  {n}^{2}  =  {(m - n)}^{2}
3)
 {x}^{2}  - 4xy + 4{y}^{2}  =  {(x - 2y)}^{2}
4)
 {a}^{2}  + 2ca +  {c}^{2}  =  {(a + c)}^{2}
5)
 {c}^{2}  + 14c + 49 =  {(c + 7)}^{2}
6)
 {k}^{2}  - 6k + 9 =  {(k - 3)}^{2}

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