Автор - Kroha19022003

хто знаэ???
1) 1-cos(270°+α)sin(180°-α)
2) cos(π+α)cos(α+2π)+sin²(α-∛π÷2)

Ответ

Проверено экспертом

Автор - Universalka

1) 1 - Cos(270⁰ + α )Sin(180⁰ - α ) = 1 - Sinα * Sinα = 1 - Sin²α = Cos²α

2) Cos(π + α)Cos(α + 2π) + Sin²(α - 3π/2) = - Cosα * Cosα + Cos²α =

= - Cos²α + Cos²α = 0

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