Автор - sveronika0307

a^2+2a+1
b^2-8b+16
c^2+10c+25
n^2+14n+49
100-20z+z^2
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Ответ

Автор - evgenrubalko11

 {a}^{2}  + 2a + 1 = ( {a + 1)}^{2}  \  {b}^{2}  - 8b + 16 = ( {b - 4)}^{2}  \  {c}^{2}  + 10c + 25 = ( {c  + 5)}^{2}  \  {n}^{2}  + 14n + 49 = ( {n + 7)}^{2}  \ 100 - 20z +  {z}^{2}  = ( {10 - z)}^{2}

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