Автор - Мляю
Ответ:
Объяснение:
log₂(5/3)+log₂(4/5)-log₄(64/9)=log₂((5/3)*(4/5))-log₄(8/3)²=
=log₂(4/3)-2*log₄(8/3)=log₂(4/3)-2*log₂²(8/3)=
=log₂(4/3)-2*(1/2)*log₂(8/3)=log₂(4/3)-log₂(8/3)=log₂((4/3)*(3/8))=
=log₂(1/2)=log₂2⁻¹=-log₂2=-1.