Ответ Автор - trscott log5(7+5x)=log5(7-x)+2log5(7+5x) - log5(7-x) = 2log5( (7+5x)/(7-x) ) = 25² = (7+5x)/(7-x)25(7-x) = (7+5x)175 - 25х = 7 + 5х30х = 168х = 168/30 = 5,6