search points attachment profile arrow left arrow right star heart verified symbols equation arrow-down question mark check menu accountancyadministrationagriculturalalgebraallarabicartart_musicbelarusbelarus_altbiologybusinesscatalachemistrychineseeconomicsegzamenglishentrepreneurshipenvironmentethicseuskarafirst_aidfrenchgalegogeographygeologygeometrygermangrammarhealthhistoryindia_langindonesian_langinformaticsitalianjapanesekazachkazach_altkoreanlanguagelatinlawlife_scienceliteraturelogicmathematicsmusicnigerian_langother_languagesotherspedagogicsphilosophyphysical_educationphysicspoliticspsychologyreligionrpa_langrussianrussian_altsciencesecurityskillssocial_sciencesociologyspanishstatisticstechnologytourismtrafficukrainianukrainian_altukrainian_literaturewos_civilisation accountancyadministrationagriculturalalgebraall_1arabicartart_music_2belarusbelarus_altbiologybusiness_2catalachemistry_1chineseeconomicsexam_3englishentrepreneurshipenvironment_2ethicseuskarasecurity_1frenchgalegogeography_4geology_4geometrygermangrammarhealthhistoryindia-langindonesian-langinformaticsitalianjapanesekazachAsset 230koreanlanguagelatinlawlife-scienceliteraturelogic_2mathematicsmusicnigerian-langotherlanguagesother_1pedagogicsphilosophyphysical_educationphysicspoliticspsychologyreligion_1rpa-langrussianrussian_altsciencesecurity_3_mskills_1allsocial_science_5_msociologyspanishstatisticstechnologytourismtrafficukrainianukrainian_altukrainian_literaturewos_civilisation
Автор - Роман1233212002

С объяснением и полным решением!

Ответ

Проверено экспертом

Автор - NNNLLL54

25); ; y=frac{x}{lnx}; ; ,; ; ODZ:; left { {{x>0} atop {lnxne 0}} right. ; ; left { {{x>0}atop {xne 1}} right. \\y'=frac{lnx-1}{ln^2x}=0; ; ,; ; lnx-1=0; ,; ; lnx=1; ,; ; x=e\\znaki; y':; ; ; (0)---(1)---[, e, ]+++++\\vozrastanie:; ; y(x); nearrow ; ; pri; ; xin [, e,+infty ); .

22); ; ctga=sqrt3\\frac{9}{sin^4a+cos^4a}=Big [; frac{:, sin^4a}{:, sin^4a}; Big ]=frac{frac{9}{sin^4a}}{1+ctg^4a}=frac{9cdot frac{1}{sin^2a}cdot frac{1}{sin^2a}}{1+(sqrt3)^4}=frac{9cdot (1+ctg^2a)^2}{1+9}=\\=frac{9}{10}cdot (1+(sqrt3)^2)^2=frac{9}{10}cdot (1+3)^2=0,9cdot 16=14,4

36); ; y=x+|x|\\|x|=left { {{x; ,; esli; xgeq 0; ,} atop {-x; ,; esli; x<0; .}} right. ; ; Rightarrow ; ; (, |x|, )'=left { {{1; ,; esli; xgeq 0; ,} atop {-1; ,; esli; x<0; .}} right. \\y'=(, x+|x|, )'=1pm 1=left { {{2; ,; esli; xgeq 0; ,} atop {0; ,; esli; x<0; .}} right. \\Otvet:; C); .

Ответы и объяснения

По всем вопросам пишите на - vashurokk@rambler.ru
© 2025 Все права защищены