Автор - lolkek8442

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Ответ

Проверено экспертом

Автор - Universalka

1)frac{a^{2}-25}{a+3}*frac{1}{a^{2} +5a}=frac{(a-5)(a+5)}{a+3}*frac{1}{a(a+5)}=frac{a-5}{a(a+3)}\\2)frac{a^{2}+10a+25 }{a^{3}-6a^{2}+9a}:frac{a+5}{a-3}=frac{(a+5)^{2} }{a(a^{2}-6a+9) }*frac{a-3}{a+5}=frac{(a+5)(a-3)}{a(a-3)^{2}}=frac{a+5}{a(a-3)}\\3)(frac{4}{a-3})^{2}=frac{16}{(a-3)^{2} }

4)frac{a-5}{a(a+3)}-frac{a+5}{a(a-3)}=frac{a^{2}-3a-5a+15-a^{2} -5a-3a-15}{a(a+3)(a-3)}=frac{-16a}{a(a+3)(a-3)}=-frac{16}{(a+3)(a-3)}\\5)-frac{16}{(a+3)(a-3)}+frac{16}{(a-3)^{2} }=frac{-16a+48+16a+48}{(a+3)(a-3)^{2} }=frac{96}{(a+3)(a-3)^{2} }

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