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Ответ:

Объяснение:

sqrt{x+6}geq0 ⇒ D(x) =(-6 ;+∞)

Пересечение с ОХ:

sqrt{x+6}-4=0\ sqrt{x+6}=4\\

возводим обе части уравнения в квадрат:

x+6=16\

x=10

Пересечение с ОУ

y=sqrt{6}-4≈-1,5

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