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Ответ дан
igundane

sinleft ( frac{x}{4} right )=-frac{sqrt{2}}{2}Leftrightarrow frac{x}{4}=(-1)^{k+1}frac{pi}{4}+pi k,kin mathbb{Z}Leftrightarrow \Leftrightarrow x=(-1)^{k+1}pi+4pi k,kin mathbb{Z}

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Universalka

15) Sinx = π - не имеет решений

16)Sinfrac{x}{4}=-frac{sqrt{2} }{2}\\frac{x}{4}=(-1)^{k}arcSin(-frac{sqrt{2}}{2})+pi k,kin Z\\frac{x}{4}=(-1)^{k}(-frac{pi }{4})+pi k,kin Z\\frac{x}{4}=(-1)^{k+1}frac{pi }{4}+pi k,kin Z\\x=(-1)^{k+1}pi+4pi k,kin Z

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