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Ответ дан
dimaogol2000

Ответ:

2

Объяснение:

Зачем вам эта проверка ? ОДЗ и хватит - лучшая проверка

sqrt{2x} -3=3-2x<=>sqrt{2x} =6-2x

ОДЗ:left { {2xgeq0 } atop {6-2xgeq0 }} right. =>0leq xleq 3

2x=(6-2x)^2<=>2x=36-24x+4x^2<=>2x^2-13x+18=0<=>\<=>(x-2)(2x-9)=0=>x=2;x=4,5

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