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АкОнИя

Ответ:

C6H12O6 = 2C2H5OH + 2CO2

55,2 - 80%

  х    - 100%

х= 55,2 : 0,8 = 69 г этанола

Нужно найти массу глюкозы:

    х                    69

C6H12O6 = 2C2H5OH + 2CO2

  180               2*46

х = (180*69) : 92 = 135 г глюкозы

Ответ: 135 г

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