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Автор - dumyanov21

(an)-арифмитическая прогрессия:3,7,11,15,.....
Найти:а:40,S:40

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Автор - anousion95

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Проверено экспертом

Автор - NNNLLL54

3; ,; 7; ,; 11; ,; 15; ,, ...\\d=7-3=4\\a_{40}=a_1+39d=3+39cdot 4=159\\S_{40}=frac{2a_1+39d}{2}cdot 40=frac{6+39cdot 4}{2}cdot 40=3240

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