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table123

Ответ:

Объяснение:

sin^2x=1-cos^2x,   тогда  2*(1-cos^2x)+3V2*cosx+2=0,  2-2cos^2x+3V2*cosx+2=0,    2cos^2x-3V2*cosx-4=0,   D=18+8*4=50=2*25

cosx=3V2+5V2/4=2V2, не удовл.,  cosx=3V2-5V2/4,   cox=-V2/2,

x=3п/4+2пn,   x=-3п/4+2пn, n  E  Z.  Отбираем корни,  это 11п/4  и 13п/4

(V- корень)

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