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Carapace2004

Задание 7:

т.к. ∆-п/у =>

 {cb}^{2}  = ab times db

16=8*DB

DB=2 см=> АD=6см (по св-ву пропорц. отр.)

Ответ: С)

Задание 8:

т.к ∆- п/у =>

 {ab}^{2}  =  {ac}^{2}  +  {bc}^{2}  \  {ab}^{2}  = 225  \ ab = 15

т.к ∆- п/у =>

 {ac}^{2}  = ab times ad

81= 15*AD

AD=5,4 см=> BD= 9,6 см

2.

 {cd}^{2}  = bd times ad

CD= 7,2см

СD-AD= 7,2-5,4= 1,8 см

Ответ: 1,8 см

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