Автор - baharovskaya

(1/3)(в степени х²) >(1/9)(в степени 8)

Ответ

Автор - 5tgb03

(1/3)^x² >(1/9)^8

(1/3)^x² >(1/3)^(8*2)

(1/3)^x² >(1/3)^16

x² < 16

|x| < 4

-4 < x < 4

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