Автор - glebnozdrin2007

помогите пажалуйста 7класс надо всё расписать дам 50 баллов
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Ответ

Автор - 1oleg2anna

Ответ:

1)

4(8 - y) = 0.2(5 - 0.5y) + 3.7

32 - 4y  = 1 - 0.1y + 3.7

 - 4y + 0.1y =  - 32 + 1 + 3.7

 - 3.9y =  - 27.3

y = 7

2)

3(x - 2) =  frac{3}{4} (5 - 4x) - 0.15

3x - 6 =  frac{15}{4}  - 3x - 0.15

3x + 3x =  frac{15}{4}  + 6 - 0.15

6x =  frac{15}{4}  +  frac{24}{4}   -   frac{3}{20}

6x =  frac{192}{20}

x =  frac{192}{120}

6x =  frac{75 + 120 - 3}{20}

 times  =  frac{192}{120}

3)

0.1 + 2(x + 5) = 3x - 5

0.1 + 2x + 10 = 3x - 5

2x - 3x =  - 5 - 0.1 - 10

5x =  - 15.1

x =  - 5.02

4)

6.7 x+    frac{4}{5} x =  frac{2}{3} (x - 20.5)

 6.7x+  0.8x = 2.3x -  frac{410}{30}

7.5x - 2.3x =  frac{410}{30}

5.2x =  frac{410}{30}

x =  frac{410}{30}  times  frac{10}{52}

x =  frac{410}{156}  =  frac{205}{78}

1)

 frac{x + 5}{4}  - 7 =  frac{7x - 3}{6}

 frac{x + 5 - 28}{4}  -  frac{7x - 3}{6}  = 0

 frac{3(x - 23) - 2(7x - 3)}{12}  = 0

 frac{3x - 69 - 14x + 6}{12}  = 0

  frac{ - 11x - 63}{12}  = 0

 - 11x - 63 = 0

 - 11x = 63

x =  -  frac{63}{11}

3)

 frac{7y + 1}{3}  -  frac{y + 1}{4}  =  frac{5y - 19}{12}

 frac{4(7y + 1) - 3(y + 1)(5y - 19)}{12}  = 0

28y + 4 - 3y - 3 - 5y - 19 = 0

20y = 18

y =  frac{18}{20}  = 0.9

4)

 frac{x - 3}{6}  +  frac{2x + 5}{3}  =  frac{2x - 6}{9}

 frac{3(x - 3) + 6(2x + 5) - 2(2x - 6)}{18}  = 0

3x - 9 + 12x + 30 - 4x + 12 = 0

11x =  - 33

x =  - 3

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