Ответ Автор - takushnir 1. f'(x)=(0.5x⁴-2x²)(㏑x+3ctgx)'=(4*0.5*x³-4x)*(㏑x+3ctgx)+(0.5x⁴-2x²)(1/x-3/sin²x)=(2x³-4x)*(㏑x+3ctgx)+(0.5x⁴-2x²)(1/x-3/sin²x)2. f'(x)=((x²+1)/(7x+1))'=(2x*(7x+1)-(x²+1)*7)/(7x+1)²=(14x²+2x-7x²-7)/(7x+1)²=(7x²+2x-7)/(7x+1)²