2cos3x-1=0
решите уравнения

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N1

2cos3x - 1 = 0

2cos3x = 1

cos3x = 1/2

3x = π/3 + 2πk

3x = -π/3 + 2πk

x = π/9 + 2πk/3

x = -π/9 + 2πk/3

Ответ : π/9 + 2πk/3 ; -π/9 + 2πk/3 ; k € Z

N2 - во вложении