ARIFMETICHESKAYA PROGRESSIYA
a2+a4+a6=24
a2*a4*a6=480
nayti kajdiy iz chlenov i obyasnite​

a1+d+a1+3d+a1+5d=24

(a1+d)*(a1+3d)*(a1+5d)=480

3a1+9d=24

a1+3d=8

a1= 8-3d

(8-3d+d)*(8-3d+3d)*(8-3d+5d)=480

8(8-2d)(8+2d)=480

32(4-d)(4+d)=480

16-d²=15

16-15=d²

d²=1

d=1  или d= -1

1) d=1

a1= 5

a2= 6

a4= 8

a6= 10

2) d= -1

a1= 11

a2= 10

a4= 8

a6= 6