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Ответ

Автор - bodan741

8)\\1);y' = 4 + frac{1}{2sqrt{x}}+cosx\2); y' = 6(3+2x)^2\3);y'=e^x+24x^5}\\9)\\1);f'(x) = 4x - 4;;f'(-1)=-8\2); y = f'(x_{0})(x-x_{0})+f(x_{0})\ f'(-1)=-8\ y = -8x-4

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