Ответ Автор - evvoronina1 (х-1)/(3х-12) - (х-3)/(2х-8)== (х-1)/3(х-4) - (х-3)/2(х-4) = =2(х-1)/6(х-4) - 3(х-3)/6(х-4) == [2(х-1) - 3(х-3)]/6(х-4) = = (2х-2-3х+9)/6(х-4) == (-х+7)/6(х-4) = -(х-7)/6(х-4)