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Автор - ATRA1MORS

Решите уравнение ((2y+3y/7)*14/17+(3y+2y/9)*27/29)*13=39

Ответ

Автор - drakerton

((2y + frac{3y}{7})*frac{14}{17} + (3y+frac{2y}{9})*frac{27}{29})*13 = 39\\(2y + frac{3y}{7})*frac{14}{17} + (3y+frac{2y}{9}*frac{27}{29}) = 39 : 13\\(2y + frac{3y}{7})*frac{14}{17} + (3y+frac{2y}{9})*frac{27}{29}) = 3\\frac{(2y+frac{3y}{7})*14}{17} + frac{(3y+frac{2y}{9})*27}{29} = 3\\29(28y + 6y) + 17(81y + 6y) = 3*17*29\\812y + 174y + 1377y + 102y = 1479\\2465y = 1479\\y = 0,6

Ответ

Автор - marialugovaya57

(17/7y*14/17+29/9y*27/29)*13=39

(y*2+y*3)*13=39

(2y+3y)*13=39

5y*13=39

65y=39

y=3/5

y=0,6

Удачи))

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