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Проверено экспертом

Автор - NNNLLL54

1); ; sqrt{asqrt{a}}=sqrt{sqrt{a^3}}=sqrt[4]{a^3}\\\2); ; a^8(a^{-2}-a^{-4})(a^4+a^5)^{-1}=a^8, (frac{1}{a^2}-frac{1}{a^4})cdot frac{1}{a^4+a^5}=\\=frac{a^2-1}{a^4}cdot frac{a^8}{a^4(1+a)}=frac{(a-1)(a+1)}{a+1}=a-1\\\3); ; (y^{frac{5}{7} })^{1,4}cdot (y^{-frac{3}{8}})^{2,4}=y^{frac{5}{7}cdot frac{14}{10}}cdot y^{-frac{3}{8}cdot frac{24}{10}}=y^1cdot y^{-frac{9}{10}}=y^{frac{1}{10}}

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