Автор - romanovaaa16

Даю 35 баллов, пожалуйста срочно помогите

3 задания

Ответ

Автор - drakerton

Ответ:

1) frac{5}{2-x} + frac{x-5}{x+2} + frac{3x+8}{x^2-4} = 0\\5(-x-2) + (x-5)(x-2) + 3x+8 = 0\\-5x -10 + x^2 - 2x - 5x + 10 + 3x + 8 = 0\\x^2 -5x - 2x - 5x + 3x - 10 + 10 + 8 = 0\\x^2 - 9x + 8 = 0\\D = 81 - 32 = 49\\sqrt{D} = 7\\x_1 = frac{9-7}{2} = frac{2}{2} = 1\\x_2 = frac{9+7}{2} = frac{16}{2} = 8\\  Otvet: boxed{x_1 = 1; x_2 = 8}

2) x^2 - 2ax + a^2 = 0\\(x-a)^2 = 0\\x - a = 0\\x = a\\frac{x}{a} = 1\\Otvet: boxed{1}

3) frac{3x}{5} = frac{x^2+8}{10}\\x^2 + 8  = 2(3x)\\x^2 - 6x + 8 = 0\\D = 36 - 32 = 4\\sqrt{D} = 2\\x_1 = frac{6-2}{2} = frac{4}{2} = 2\\x_2 = frac{6+2}{2} = frac{8}{2} = 4\\Otvet: boxed{x_1 = 2; x_2 = 4}

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