Автор - Ueban2281488
(2x+3) / (x+2) = (3x+2) / x,
х(2x+3) / х(x+2) = (х+2)(3x+2) / x(х+2),
(2x²+3х) / х(x+2) = (3х²+2х+6х+4) / x(х+2),
(2x²+3х - 3х²-2х-6х-4) / x(х+2) = 0,
(-х²-5х-4) / x(х+2) = 0,
ОДЗ:
x(х+2) ≠ 0,
х ≠ 0, х+2 ≠ 0,
х ≠ -2,
-х²-5х-4 = 0,
х² + 5х + 4 = 0,
Д = 5² - 4*1*4 = 25 - 16 = 9,
х1 = (-5 + 3) / 2*2 = -2/2 = -1,
х2 = (-5 - 3) / 2*1 = -8/2 = -4