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Автор - hakerroma630

ПОМОГИТЕ ПОЖАЛУЙСТА
А) в обыкновенных
Б) в десятичных

Ответ

Автор - alan73
1a)3/20 б)2,4
....................

Ответ

Автор - drakerton

Решение:

1a) 1frac{1}{3}x = 0,3\ \x = frac{3}{10} : frac{4}{3} = frac{3*3}{10*4} = frac{9}{40}

1b) 1frac{1}{4}x = 5,5\ \1,25x = 5,5\\x = 5,5 : 1,25 = 4,4

2a) a + 0,2a + frac{3}{7}a = 1\ \frac{6}{5}a + frac{3}{7}a = 1  \\frac{42+15}{35}a = 1\\frac{57}{35} a = 1\ \a = frac{35}{57}

2b) b + frac{1}{4}b + 0,75b = 1\ \b + 0,25b + 0,75b = 1\\2b = 1\\b = 0,5

3a) 3,8(b-1frac{1}{6}) = frac{19}{20}\ \frac{19}{5}b - (frac{19}{5} : frac{7}{6}) = frac{19}{20}\\frac{19}{5}b - frac{19*6}{5*7} = frac{19}{20}\\frac{19}{5}b = frac{19}{20} + frac{114}{35}\\frac{19}{5}b = frac{133+456}{140} =  frac{589}{140}\\b = frac{589*5}{140*19} = frac{31}{28} = 1frac{3}{28}

3b) 1frac{1}{4}(b -1,2) = 5,5\\1,25b - 1,5 = 5,5\\1,25b = 5,5 + 1,5\\1,25b = 7\\b = 7 : 1,25\\b = 5,6

4a) (m-frac{3}{7}) : 1frac{1}{5} = 3,5\  \m - frac{3}{7} = frac{7}{2} * frac{6}{5}\   \m - frac{3}{7} = frac{21}{5}\ \m = frac{21}{5} + frac{3}{7} = frac{147+15}{35} \  \m = frac{162}{35} = 4frac{22}{35}

4b) (2,3 - m) : frac{3}{5} = 0,12\ \2,3 - m = 0,12 * 0,6\\2,3 - m = 0,72\\m = 2,3 - 0,72\\m = 1,58

5a) frac{17}{4,3-c} = 5,1\\4,3 - c = frac{17}{5,1} = 17 : frac{51}{10} = frac{17*10}{51} = frac{10}{3}\    \c = frac{43}{10} - frac{10}{3} = frac{129-100}{30} = frac{29}{30}

5b) frac{0,4}{c - frac{3}{4}} = 1frac{1}{3}\  \c - frac{3}{4} = frac{2}{5} : frac{4}{3}\   \c - frac{3}{4} = frac{2*3}{5*4} = frac{6}{20} = frac{3}{10}\\c = 0,3 + 0,75\\c = 1,05

6a) 5x - frac{1}{2} = frac{5}{6}\ \5x = frac{5}{6} + frac{1}{2} \\5x = frac{5+3}{6} = frac{8}{6} = frac{4}{3}\   \x = frac{4}{3} : 5 = frac{4}{3} * frac{1}{5} = frac{4}{15}

6b) 2frac{5}{6} - 5x = 1frac{1}{3}\ \5x = 2frac{5}{6} - 1frac{1}{3} \ \5x = frac{17}{6} - frac{4}{3} = frac{17-8}{6} = frac{9}{6}\    \5x = 1,5\\x = 1,5 : 5\\x = 0,3

7a) (2t - 3frac{4}{15}) * 1,3 = frac{13}{25}\  \2,6t - frac{49}{15}* frac{13}{10} = frac{13}{25}\  \2,6t = frac{13}{25} + frac{637}{150}\ \2,6t = frac{78+637}{150} = frac{715}{150}\ \t = frac{715}{150} : frac{13}{5} = frac{715*5}{150*13} = frac{55}{30} = 1frac{25}{30} = 1frac{5}{6}

7b) 2,25 + 0,5(11-3x) = 4frac{3}{8}]\ \2,25 + 5,5 - 1,5x = 4,375\\7,75 - 1,5x = 4,375\\1,5x = 7,75 - 4,375\\1,5x = 3,375\\x = 3,375 : 1,5\\x = 2,25

8a) 6 - (2,2x - 1frac{1}{7}) * 1frac{1}{6} = 5,5\  \6 - (frac{11}{5}x * frac{7}{6} + frac{8}{7}*frac{7}{6}) = 5,5\    \frac{11}{5}x * frac{7}{6} + frac{8}{7}*frac{7}{6} = 6 - 5,5\\frac{11}{5}x * frac{7}{6} + frac{8}{7}*frac{7}{6} = 0,5\\frac{77}{30}x + frac{4}{3} = frac{1}{2}\\frac{77}{30}x = frac{1}{2} - frac{4}{3} =frac{3-8}{6}\\frac{77}{30}x = -frac{5}{6}\  \x = -frac{5}{6} : frac{77}{30} = -frac{5*30}{6*77} = -frac{25}{77}

8b) 5frac{6}{7}(2frac{1}{4} - 0,25x) = 0,41\  \2,25 - 0,25x = frac{41}{100} : frac{41}{7} = frac{41*7}{100*41} = 0,07\  \0,25x = 2,25 - 0,07 = 2,18\\x = 2,18 : 0,25 \\x = 8,72

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