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nikitalomantsov

Ответ:

Пошаговое объяснение:

(15^(2/3)*3^(7/3))/5^(-1/3)=

(3^(2/3)*5^(2/3)*3^(7/3))/5^(-1/3)=

3^(9/3)*5^(1/3)=27*5^(1/3)

2)(4/5)^(-2)-(1/27)^(1/3)+4=25/16-1/3+4=59/48+4=251/48

3)(128^(1/3)+(1/4)^(1/3))/2^(1/3)=

((4*(2^(1/3))+(1/4)^(1/3))/2^(1/3)=4+(1/8)^(1/3)=4+1/2=9/2

4)((ab^2)/c)^(1/3)*((a^5b)/c^2)^(1/3)=((a^6b^3)/c^3)^(1/3)=(a^2b)/c

5)(a^(-3)*a^(7/3))/a^(1/3)=1/a

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