Автор - arturchik31

Разложить
1)1-a^2: 2) a^2-100: 3) 16-x^2: 4) b^2 -4​

Ответ

Автор - DavidGoodwin

1)1-a^2 = (1-a)*(1+a)

2) a^2-100=a^2 - 10^2=(a-10)*(a+10)

3) 16-x^2=4^2-x^2=(4-x)*(4+x)

4) b^2 -4=b^2 - 2^2=(b-2)*(b+2)

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