Автор - vladmutar200
SinB=AC/AB=√91/10; SinA=CB/AB=3/10=0,3
cosB=CB/AB=0,3; cosA=AC/AB=√91/10
tgB=AC/BC=√91/3; tgA=CB/AC=3/√91
ctgB=CB/AC=3/√91; ctgA=AC/CB=√91/3.
Sin∠B=cos∠A=AC/AB=√91/10;
Sin∠A=cos∠B=CB/AB=3/10=0,3
tg∠B=ctg∠A=AC/BC=√91/3;
tg∠A=ctg∠B=CB/AC=3/√91=3√91/91