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Автор - bcq26989

УМОЛЯЮ СРОЧНО!!!!!!!!

Ответ

Автор - 5187404

Ответ:

Объяснение:

а

D=-8, x1=frac{4+sqrt{-8} }{6}, x2=frac{4-sqrt{-8} }{6}

б

11x^{2} +12=25x-x^{2} \12x^{2} -25x+12=0\D=49, x1=frac{4}{3}, x2=frac{3}{4}

в

(3-m)^{2} =4m(m-3)-15\9-6m+m^{2}=4m^{2}-12m-15\-3m^{2}+6m+24=0\D=-324, x1=-4, x2=2

г

frac{4y^{2}+3 }{15}-frac{2y}{5}=frac{5-2y}{10}-frac{1}{3}\\frac{2(4y^{2}+3)}{30}-frac{6*2y}{30}=frac{3(5-2y)}{30}-frac{10}{30}\\8y^{2}+6-12y=15-6y-10\8y^{2}-6y+1=0\D=4, x1=frac{1}{2}, x2=frac{1}{4}

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